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Deffense [45]
3 years ago
9

What is the measure of an arc intercepted by an inscribed angle whose measure is 88 degrees

Mathematics
1 answer:
I am Lyosha [343]3 years ago
7 0

Answer:

176\°

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc it comprises.

so

In this problem

Let

x-----> the measure of an arc intercepted by an inscribed angle

88\°=\frac{1}{2}(x)

x=2(88\°)=176\°

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Julien's parents want $64,000 at the end of 3 years. They put their money in an account that yields 10% per year compounded mont
Leto [7]

Answer: \$47,471

Step-by-step explanation:

Given

Julien's parents want $64,000 at the end of 3 years

The rate of interest is 10% annually

Suppose they invested P amount initially

So, compound interest, compounded monthly is

\Rightarrow A=P\left( 1+\frac{r}{n}\right)^{nt}\quad [\text{n=Numner of compounding periods}]\\\\\text{Insert the values}\\\Rightarrow 64,000=P\left( 1+\frac{0.10}{12}\right)^{12\times 3}\\\\\Rightarrow 64,000=P\left( 1+\frac{10}{12}\right)^{36}\\\\\Rightarrow P=\dfrac{64000}{1.3481}\\\\\Rightarrow P=\$\ 47,471.37\approx \$ 47,471

7 0
3 years ago
Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu
goldenfox [79]

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

49.2 + 19.25 + 14.7 = 83.15

4 0
3 years ago
A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
Please help and show work<br>​
Sunny_sXe [5.5K]

Answer:

Just do scan and solve by brainly really helpful ngl

Step-by-step explanation:

5 0
2 years ago
What is the area of a trapezoid? 47,45,65
Masteriza [31]
Area = 2,520m^2
(47+65)/2 = 56
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8 0
2 years ago
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