Answer:
9990bacterias
Step-by-step explanation:
Using the formula for finding rate of decay.
N(t) = Noe^-kt
No is the initial population
N(t) is the population during time ,t
If bacteria population declined from 100,000 to 100 in 24 hours
No = 100,000, N(t) = 100, t = 24
Substituting to get the constant k
100 = 100000e^-24k
0.001 = e^-24k
Taking ln of both sides
ln0.001 = lne^-24k
-6.91 = -24k
k = 6.91/24
k = 0.288.
To know the number of bacteria there after 8hours,
N(8) = 100,000e^-0.288(8)
N(8) = 100,000e^-2.304
N(8) = 100,000×0.0999
N(8) = 9,990bacterias
