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weeeeeb [17]
3 years ago
12

Paige has 1 ½ feet of rope for a project. She only needs 2/3 of it. How much rope does she need?

Mathematics
2 answers:
Grace [21]3 years ago
4 0

Answer:

1 foot

Step-by-step explanation:

1 1/2 = 3/2

2/3*3/2 = 1

Strike441 [17]3 years ago
4 0

Answer:

1 foot of rope.

Step-by-step explanation:

For this problem, we need to find 2/3 of 1 ½. 1 ½ equals 3/2. Since the word "of" means multiply, we multiply 3/2 by 2/3. When we do this, we get 1. This means Paige needs 1 foot of rope. I hope this helps!

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Which of the following sequences of numbers are arithmetic sequences?
Pepsi [2]
Answer: B, C, E

-------

The difference between consecutive terms (numbers that come after each other) in arithmetic sequences is the same. That means you add the same number every time to get the next number. To figure out which choices are arithmetic sequences, just see if the differences are the same.

Choice A) 1, -2, 3, -4, 5, ...
-2 - 1 = -3
3 - (-2) = 5
The difference is not constant, so it is not an arithmetic sequence.

Choice B) 12,345, 12,346, 12,347, 12,348, 12,349, ... 
12,346 - 12,345 = 1
12,347 - 12,346 = 1
The difference is constant, so it is an arithmetic sequence.

Choice C) <span>154, 171, 188, 205, 222, ... 
171 - 154 = 17
188 - 171 = 17
The difference is constant, so it is an arithmetic sequence.

Choice D) 
</span><span>1, 8, 16, 24, 32, ...
8 - 1 = 7
16 - 8 = 8
</span>The difference is not constant, so it is not an arithmetic sequence.

Choice E) 
<span>-3, -10, -17, -24, -31, ...
-10 - (-3) = -7
-17 - (-10) = -7
</span>The difference is constant, so it is an arithmetic sequence.
5 0
3 years ago
Bag contains 4 red marbles, 2 blue marbles, 1 purple
GaryK [48]

Answer:

432

Step-by-step explanation:

6 0
2 years ago
Anna, Beth and Colleen are softball players. This season, Anne had 65 base hits in 160 at-bats. Beth batting average was 0.399,
zheka24 [161]

Answer:

Anne is the best hitter as she has the best hitting average of 0.406

Step-by-step explanation:

Anne hits 65 bases out of 160 at - bats.

Beth's betting average = 0.399

Collin's hit = 40%

Now, we need to convert all the three hitting rates into same parameters to compare them with each other.

Average hit rate of Anne = \frac{\textrm{Total numberof base}}{\textrm{Total number of  at - bats}}

= \frac{65}{160}  = 0.406

⇒The betting average of Anne = 0.406

Now, The hit - rate of Collin = 40%

Converting the percentage rate into decimal, we get the hit rate of Collin

= \frac{40}{100}  = 0.40

Hence, we get that Hitting Average of :

<u>Anne = 0.406</u>,  Beth = 0.3999 and Collin = 0.400

Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.

6 0
3 years ago
Read 2 more answers
There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes ther
Novay_Z [31]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
2 years ago
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