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mars1129 [50]
3 years ago
5

An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20cm.

Mathematics
1 answer:
Komok [63]3 years ago
6 0
We know that
the area A of the circular cross section of the pipe is
A=pi*r²
D=20 cm------------- > r=D/2=20/2=10 cm
then
A=pi*10²=100*pi cm²

the answer is A=100*pi cm²
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Find the lowest number of four digits that can be divided by 22,36,and 42​
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Answer:

find the lcm of 22,36,and 42

Step-by-step explanation:

lcm of 22 = 11 x 2

lcm of 36 = 2 x 2 x 3 x 3

lcm of 42 = 2 x 3 x 7

so the lcm of three numbers are 11 x 2 x 2 x 2 x 3 x 3 2 x 3 x 7 = 1000

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3 years ago
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The given equation has been solved in the table.
Ivahew [28]

Answer:

D.

Step-by-step explanation:

The subtraction property involves subtracting the same number that is subtracted from one side of the equal sign and also subtracting same from the other side of the equal sign

For example: y + 3 = 2

To apply the subtraction property, subtract 3 from each side. Thus:

y + 3 = 2 - 3

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3 years ago
Ray is planning to open a video game store. He has developed the following expense breakdown for set-up and operation for the fi
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Answer:

Yes

Step-by-step explanation:

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3 years ago
A coin contains 999 grams of nickel and 161616 grams of copper, for a total weight of 252525 grams.
Sedbober [7]

Answer:

X=64%

Step-by-step explanation:

The percentage of Cooper in the coin is 64%

How do you come to this conclusion?

252525--100%

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3 years ago
Find the area of the shaded region
VikaD [51]

Answer:

Area of the shades region = 244.6 ft²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle ABCD- Area of the right angle triangle DEC

Area of the rectangle = Length × width

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By applying Pythagoras theorem in the right triangle DEC,

(Hypotenuse)² = (leg 1)² + (leg 2)²

CD² = DE² + EC²

(29.8)² = DE² + (28)²

888.04 = DE² + 784

DE² = 888.04 - 784

DE = 10.2 ft

Area of ΔDEC = \frac{1}{2}(\text{Base})(\text{Height})

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Area of the shades region = 387.4 - 142.8

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4 0
3 years ago
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