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Mademuasel [1]
3 years ago
9

Graph the line that passes through the points (-2,2) and (-4,2) and determine the equation of the line

Mathematics
1 answer:
Naily [24]3 years ago
6 0

y = 2. That's your equation.

The graph is the attachment.

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A rectangle has an area of 8 square centimmetres and a perimeter of 12 cm. What are the width and breath?
vlada-n [284]
Let the Length be L and the Width be W

The area is 8 cm²
LW = 8

The perimeter is 12
2(L + W) = 12
L + W = 6

Solve L and W:
LW = 8 --------------- (1)
L + W = 6------------ (2)

Equation (2):
L + W = 6
L = 6 - W -------------- Sub into (1)
(6 - W) W = 8
6W - W² = 8
W² - 6W + 8 =0 
(W -2 )(W - 4) = 0
W = 2 or 4

When W =2, L = 6 - 2 = 4
When W = 4, L = 6 - 4 = 2

Answer: The Width is 2 cm and the Length is 4 cm
8 0
3 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0
3 years ago
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