Let

If M is the midpoint, the x and y coordinates of M are the average of the x and y coordinates of P and Q:

We can solve this expression for the coordinates of Q:


Plug in the values for the coordinates of M and P to get


There is no work to show. It is really just trial and error till you get the hang of it. You look at the multiples of the last term and find.which add or subtract to the middle terms coefficient. Use DeCartes law of signs to determine if it is plus or minus.
1. Does not factor solve using other method
2. (X-5)^2
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Answer:
first one is 82% second is 214%
Step-by-step explanation:
Step 1: Divide 288 by 351 to get the number as a decimal. 288 / 351 = 0.82
Step 2: Multiply 0.82 by 100. 0.82 times 100 = 82
Step 1: Divide 212 by 99 to get the number as a decimal. 212 / 99 = 2.14
Step 2: Multiply 2.14 by 100. 2.14 times 100 = 214
Answer:
The mean is 
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the mean of this normal distribution if the probability of scoring above x = 209 is 0.0228?
This means that when X = 209, Z has a pvalue of 1-0.0228 = 0.9772. So when X = 209, Z = 2.





The mean is 