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Alja [10]
3 years ago
6

If f(x)= 3x2 and g(x) = x+2, find (f.g)(x).

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

Step-by-step explanation:

f(x) = 3 {x}^{2}  \: and \: g(x) = x + 2 \\ (f.g)(x)  \\ = f(x).g(x) \\  = 3 {x}^{2} .(x  + 2) \\ \red{ \boxed{ \bold{  \therefore f(x).g(x)= 3 {x}^{3}  + 6 {x}^{2} }}} \\

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If your correct i will give u brainlist :)))))))))))
TiliK225 [7]

Answer:

This is not the answer this is the trick to find it

Step-by-step explanation:

The points after reflection will follow points equal but different direction, to the path followed before the reflection. So, if the line would cover 3.5 on the x and 5 on the y; it will reflect symmetrically giving you the formula to get your answer.

7 0
3 years ago
A game consists of rolling a colored die with three red sides, two green sides, and one blue side. A roll of a red loses. A roll
Pavel [41]

The expected value of the game is $2.00.

To Find: The fair price to pay to play the game of rolling a colored die with three red sides, two green sides, and one blue side

Now the question arises how to find the Fair Price

We are told that in the game of rolling the colored die;

A roll of a red loses.

A roll of blue pays 5.00 and A roll of green pays 2.00.

Now, the best game to get the fairest price is to play; RRRGGB  i.e (RED, RED, RED, GREEN, GREEN,BLUE)

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Read more about Fair Price at; brainly.com/question/24855677

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7 0
2 years ago
PLEASE HELP! Which table shows a proportional relationship between x and y?
Inga [223]
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5 0
3 years ago
Which number line illustrates the problem below? x = -1 - (-2) -3
Alina [70]
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5 0
4 years ago
I am offering another 100 points
Ivahew [28]

Answer:

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find \sf \sqrt{75} , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

  • 64 and 81

\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}

\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.

See the attachment for the correct placement of \sf \sqrt{75} on the number line.

6 0
1 year ago
Read 2 more answers
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