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Shalnov [3]
3 years ago
5

Prove, using the second derivative, that the general quadratic y= ax^2+bx+c, is:

Mathematics
1 answer:
lozanna [386]3 years ago
3 0

There are three things you have to know:

  • A function is convex when its second derivative f''(x)>0
  • A function is concave when it second derivative f''(x)
  • The derivative of a power, x^n, is nx^{n-1}

So, the first derivative is

y'=2ax+b

and the second derivative is

y''=2a

This implies that the second derivative of a parabola is constant, and of course that 2 doesn't change the sign of a.

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A spinner numbered 1 through 12 is spun. Find the probability that
anastassius [24]

Answer:

\dfrac{1}{6}

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. \{1,3,5,7,9,11\}

Here, total numbers in the game are 12 i.e \{1,2,3,....,12\}.

Formula for probability of an <em>event E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

P(B) = \dfrac{1}{12}

P(A \cap B) is the probability that we get 11 and an odd number.

Possible number of cases = 1

P(A\cap B) = \dfrac{1}{12}

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}

Hence, P(B/A) = \dfrac{1}{6}

4 0
3 years ago
Read 2 more answers
Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per
AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.

Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>

Which by cross-multiplying gives <em>distance = speed × time</em>.

Let time taken to cover the distance be <em>t h</em>.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

      t² = 225/(49 + 81)

      t² = 225/130

      t² = 1.730769231

       t = √1.730769231

       t = 1.315587029

t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0
3 years ago
Rewrite 5ab showing the multiplication signs
monitta

Answer:

5ab = 5 \times a \times b

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Hillary is making a blanket for her mom. Three fourths of the blanket is green and the rest is yellow. Two thirds of the yellow
Leviafan [203]

Answer:

1/6

Step-by-step explanation:

Hillary is making a blanket for her mom.

Let the total blanket = 1

Three-fourths of the blanket is green and the rest is yellow.

The fraction for the rest(yellow portion) = 1 - 3/4

The Lowest Common Denominator is 4

Hence,

4 - 3 /4 = 1/4

Two-thirds of the yellow part has her name on it.

The fraction of the blanket that will have her name on it is calculated as

2/3 of 1 /4

= 2/3 × 1/4

= 1/6

4 0
3 years ago
You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?
puteri [66]

Answer:

15

Step-by-step explanation:

lets begin to set up this question. i personally find questions like these easiest when i begin to set up ideas to help my brain process it better, for example:

person a

person b

person c

person d

we know that each (person) must receive at least 1 candy. we also know that we have 7 candies. therefore if we want do draw this out :

person a- 1

person b- 1

person c- 1

person d -1

notice that we now have given away 4 of the 7 candies. now we have 3 candies left. we can simply:

person a- 2

person b-2

person c-2

person d- 1

but, keep in mind that there are still many more ways that we can distribute the candies to other kids. the question we are asked is how may ways can we do this. since i have already illustrated the question, you can either learn how to put this into an equation, or experiment how many variations there are. the answer, either way is 15.

4 0
3 years ago
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