I trying to simplify ( 14+5) +15÷2 PLEASE HELP this is a 5th grade math question

Mathematics

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

14+5 = 19

19 + 15/2

15/2 = 7.5

19+7.5 = 26.5

Just remember PEMDAS!

Pls mark brainliest

Step-by-step explanation:

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I don’t understand this someone pls help

omeli [17]

To solve this, you need to plug in the numbers for <em>h</em>.

-4(-12) ≥ 8 48 ≥ 8 yes

-4(-7) ≥ 8 28 ≥ 8 yes

-4(-5) ≥ 8 20 ≥ 8 yes

-4(-3) ≥ 8 12 ≥ 8 yes

-4(-2) ≥ 8 8 ≥ 8 yes

-4(-1) ≥ 8 4 ≥ 8 no

-4(1) ≥ 8 -4 ≥ 8 no

-4(3) ≥ 8 -12 ≥ 8 no

-4(8) ≥ 8 -32 ≥ 8 no

Hope this helped!

7 0

3 years ago

102, 163, 185, 111, 215, 137, 158, 125, 195, 205

Nata [24]

Answer:

160.5

Step-by-step explanation:

Arrange the data in an ascending order and the median is the middle value. if the number of values is an even number, the median will be the average of the two middle numbers.

8 0

2 years ago

Read 2 more answers

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$