Which of the following is an extraneous solution of square root -3x-2=x+2?

2 answers:

6 0

Hello,

Answer A (x=-6 is an extraneous solution)

√(-3x-2)=x+2
==>-3x-2>=0
==>x<= -2/3

So -3x-2=(x+2)²
==>-3x-2=x²+4x+4
==>x²+7x+6=0
==> (x=-6) or (x=-1)

if x=-6 then
√(-3*(-6)-2)=√16=4
-6+2=-4
False 4≠-4

if x=-1
√(-3*(-1)-2)=√1=1
-1+2=1
ok..

Reika [66]3 years ago

6 0

Answer:

A. x=-6

Step-by-step explanation:

i got it right on edge

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