Which of the following is an extraneous solution of square root -3x-2=x+2?
2 answers:
Hello,
Answer A (x=-6 is an extraneous solution)
√(-3x-2)=x+2
==>-3x-2>=0
==>x<= -2/3
So -3x-2=(x+2)²
==>-3x-2=x²+4x+4
==>x²+7x+6=0
==> (x=-6) or (x=-1)
if x=-6 then
√(-3*(-6)-2)=√16=4
-6+2=-4
False 4≠-4
if x=-1
√(-3*(-1)-2)=√1=1
-1+2=1
ok..
Answer:
A. x=-6
Step-by-step explanation:
i got it right on edge
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