SOLUTION
Given B is the midpoint of AC ABBC 1 and C is the midpoint of BD BCCD2 ie on adding 1 and 2 ART We get ABBCBCCD hence ABCD hence proved
Answer:
The area of a circle is pi times the radius squared (A = π r²).
Step-by-step explanation:
(I'm not sure how to explain this further)
Hope this helps!
-Coconut;)
Answer: This is late but they can expect to pay b.)56.25%
Answer:
Step-by-step explanation:
CD is Pole
∠CAD = 4° {Alternate interior angles}
ΔCAD,

In ΔCDB,
∠B = 5° {Alternate interior angles}
