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3 years ago

The slope of the line below is -2. Use the coordinates of the labeled point to

Mathematics

1 answer:

Vilka [71]3 years ago

6 0

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

$y(x)=mx+b\\\\y(x)=-2x+b$

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

$y_0=-2x_0+b$

Then, we can calculate b as:

$y_0=-2x_0+b\\\\b=y_0+2x_0$

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

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elena-14-01-66 [18.8K]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Write the equation of the line shown in point-slope form. (2,1) (3,8)

Ulleksa [173]

Answer:

The line equation that passes through the given points is 7x – y = 13

Explanation:

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ ..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

$(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)$

$(y -8) = \frac{(- 7)}{(-1)}(x-3)$

y – 8 = 7(x – 3)

y – 8 = 7x – 21

7x – y = 21 – 8

7x – y = 13

Hence, the line equation that passes through the given points is 7x – y = 13

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3 years ago