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stiks02 [169]
3 years ago
15

Find the range of f(x) = –x + 4 for the domain {–3, –2, –1, 1}.

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

\boxed{ \{7, 6, 5, 3 \} }

Step-by-step explanation:

The domain is all possible values for x.

The range is all possible values for f(x) or y.

The domain given is {-3, -2, -1, 1}.

Plug x as {-3, -2, -1, 1} and find the f(x) or y values.

f(-3)=-(-3)+4=7\\f(-2)=-(-2)+4=6\\f(-1)=-(-1)+4=5\\f(1)=-(1)+4=3

The range is {7, 6, 5, 3}, when the domain is {-3, -2, -1, 1}.

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<span>C. Square
It could not be A. Most likely its C. So you can pick both or just C.</span>
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56 books; 75% decrease
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75% of 56 is .75 * 56
.75 * 56 = 42
Because you are decreasing, you subtract 42 from 56.
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A 75% decrease of 56 books would leave 14 books.
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Please help I don't know how to do this I am confused
Zarrin [17]

Answer:

not congruent

Step-by-step explanation:

angles are not equal

3 0
2 years ago
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
2. In order to go to college, Howard goes from working full-time making $33,000 per year to working part-time at half the
Ipatiy [6.2K]

Answer:4

Step-by-step explanation:

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2 years ago
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