Answer:
S'(5,-1), M'(1,-3)
Step-by-step explanation:
So, if the rotation is clockwise, the formula is (x,y)--->(-x,-y).
The original points are, (-1,3) and (-5,1).
Using the formula,
(-1,3) ----> (1,-3)
(-5,1) ----> (5,-1)
For the question in the image, the reflection over the x-axis is..
S'(-5,1) ---> (-5,-1)
M'(1,-3) ---> (-1,-3)
Answer:
<h3>1. t=10</h3><h3>2. t=4</h3><h3>3. t=40</h3>
Step-by-step explanation:
Isolate the term of t from one side of the equation.
<h3>1. 4t=40</h3>
First, you have to divide by 4 from both sides.
4t/4=40/4
Solve.
Divide the numbers from left to right.
40/4=10
<h3><u>
t=10</u></h3>
<h3>2. 10+t=14</h3>
<u>First, change sides.</u>
t+10=14
<u>Then, subtract by 10 from both sides.</u>
t+10-10=14-10
<u>Solve.</u>
<u>Subtract the numbers from left to right.</u>
14-10=4
<h3><u>
t=4</u></h3>
<h3>3. 70-t=30</h3>
First, subtract by 70 from both sides.
70-t-70=30-70
Solve.
30-70=-40
<u>Rewrite the problem down.</u>
-t=-40
Divide by -1 from both sides.
-t/-1=-40/-1
<u>Solve.</u>
<u />
<u>Divide the numbers from left to right.</u>
-40/-1=40
<h3><u>
t=40</u></h3>
- <u>Therefore, the correct answer is t=10, t=4, and t=40.</u>
I hope this helps! Let me know if you have any questions.
Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
Sorry if my handwriting sloppy.
I showed all of it step by step.
