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guapka [62]
2 years ago
13

Solve the following linear inequality: 3(x + 4) ≥ 5x – 123

Mathematics
2 answers:
Tpy6a [65]2 years ago
6 0
3(x+4)\geq5x-123\\3\cdot x+3\cdot4\geq5x-123\\3x+12\geq5x-123\ \ \ \ /-12\\3x\geq5x-135\ \ \ \ /-5x\\-2x\geq-135\ \ \ /:(-2) < 0\ then\ "\geq"\ change\ "\leq"\\x\leq67.5\\\\x\in(-\infty;\ 67.5 >
bagirrra123 [75]2 years ago
3 0
3(x + 4) \geq 5x - 123 \\&#10;3x+12\geq5x-123\\&#10;2x\leq135\\&#10;x\leq\frac{135}{2}&#10;
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Please help me with this , it would mean alot​
algol [13]

Answer:

Step-by-step explanation:

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=> a = 47 - 19 / 5

=> a = 28 / 5

=> a = 5.6 m/s²

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4 0
2 years ago
Theorem: A line parallel to one side of a triangle divides the other two proportionately.
Elenna [48]

Answer:

Segment BF = 16 is true.

Step-by-step explanation:

Since, DE is parallel to BC, so DE will divide AB and AC proportionally.

Hence,

\frac{AE}{EC}  = \frac{AD}{DB}

⇒  \frac{12}{18}  = \frac{6}{DB} 

{Since, given that AE = 12, EC = 18 and AD = 6}

⇒ BD = 9.

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Hence, \frac{CE}{AE}  = \frac{FC}{BF}

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3 0
3 years ago
-25 - 30 + 2 = pls help
Galina-37 [17]

Answer:

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5 0
2 years ago
PLZ HELP! MAAAATH! image attached
Elena L [17]

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4 0
3 years ago
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aleksley [76]

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Hope this can help you.

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3 years ago
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