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guapka [62]
3 years ago
13

Solve the following linear inequality: 3(x + 4) ≥ 5x – 123

Mathematics
2 answers:
Tpy6a [65]3 years ago
6 0
3(x+4)\geq5x-123\\3\cdot x+3\cdot4\geq5x-123\\3x+12\geq5x-123\ \ \ \ /-12\\3x\geq5x-135\ \ \ \ /-5x\\-2x\geq-135\ \ \ /:(-2) < 0\ then\ "\geq"\ change\ "\leq"\\x\leq67.5\\\\x\in(-\infty;\ 67.5 >
bagirrra123 [75]3 years ago
3 0
3(x + 4) \geq 5x - 123 \\&#10;3x+12\geq5x-123\\&#10;2x\leq135\\&#10;x\leq\frac{135}{2}&#10;
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Answer:

the third obtuse angle is 110°.

Step-by-step explanation:

From the question, the 0s at the back of the given angles are meant to be degrees (°), since the sum of angles in a triangle cannot exceed 180°.

Hence, The question would be:

The two angles of an obtuse triangle are 23° and 47°. Find the third obtuse angle .

Step-by-step explanation:

In a triangle, there are three (3) angles which sum up to 180°.

Two of the angles are given which are 23° and 47°. Now, to determine the third angle which is an obtuse angle.

(NOTE: An obtuse angle is a type of angle that is greater than 90° but less than 180°).

Let the third obtuse angle be x

Then , we can write that

23° + 47° + x = 180° (Sum of angles in a triangle)

Then,

70° + x = 180°

x = 180° - 70°

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Hence, the third obtuse angle is 110°.

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Hope this helps!

(Hint: M = Slope)



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