Question

Can someone please help me with #10 and #11

Answer 1

10) S is the midpoint of RT.
Sx= Rx+Tx/2=2
Tx=13
Sy=Ry+Ty/2= -1
Ty= -1
T=(13,-1)

11) Sx=Rx+Tx/2=-4
Rx= -1
Sy=Ry+Ty/2= -6
Ry= -9
R=(-1,-9)

12)B is midpoint of AC.
Bx= Ax+Cx/2=-5
By= Ay+Cx/2= 1
B=(-5,1)

E is midpoint of BD.
Ex= Bx+Dx/2=-4
Dx=-3
Ey=By+Dy/2=-3
Dy=-7
D=(-3,-7)

Answer 2

Answer:

10 ) T= (-5,2)  

11 ) R = (-1,-9)

Step-by-step explanation:

given in the question,

S is midpoint of line segment RT

10) to find T

points given R(9,-4) and S(2,-1)

2 = \dfrac{9 + x}{2}                 -1 = \dfrac{-4 +y }{2}

  x = -5                                       y = 2

hence, T= (-5,2)                                        

11) to find R                                      

given, S(-4,-6) and T(-7,-3)

 -4 = \dfrac{x-7}{2}                   -6 = \dfrac{y-3}{2}

  x = - 1                                       y = -9

hence, R = (-1,-9)