In the end, Wally makes $2 (profit)
-$5,+$6,-$7,+$8
Commutative property of multiplication
Answer:
377 choices
Step-by-step explanation:
From the above question, we are told that
A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
M = Main meal = 8
D = Dessert = 5
a) The combination of the 3 choices together
AMD=6 × 8 × 5=240
b) AM= Appetizer and Main meal
= 6 × 8 = 48
c) AD= Appetizer and Dessert
= 6 × 5 = 30
d) MD = Main meal × Dessert
= 8 × 5 = 40
e) A,M,D (each alone)=
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19
Assuming all choices are available, how many different possible meals does the restaurant offer?
This is calculated as:
AMD + AM + AD + MD + A,M,D
240 + 48 + 30 + 40 + 19
= 377 choices
Answer:
True.
We can see that the line goes through (0, 0), however, the line is not dotted, therefore that point is included. (0,0) also coincides with the other inequality, which means that (0, 0) is a solution.
Answer:
Parallel line: - 1/2
Perpendicular line: 2
Step-by-step explanation:
