AC would be double of its angle, which happens to be 58.
58•2 = 116.
Therefore, your answer would be D: 116 degrees.
T(t)=e−kt(∫ekt[KM(t)+H(t)+U(t)]dt+C)
M is the outside temperature, H is other things that affect temperature
in the tank(0 in this case), and U is the solar panel. K comes from the
time constant, and should be the inverse of the time constant I believe.
T is temperature, t is time.
T(t)=e−164t(∫e164t[164(80)+4t]dt
After integrating I keep getting
−16304+256t+Ce−164t
I calculate C to be 16414 setting t equal to 0 and using the initial conditions
To measure George's rate of change, we first set out two pairs of independent and dependent data which in this case is the day number and the point
Independent Data: Day 2 Independent Data: Day 4
Dependent Data: 8 points Dependant Data: 12 points
Then we find the difference between the two independent values and the two dependent values
4 - 2 = 2
12 - 8 =4
To find the rate we use the following formula
the difference of dependent value ÷ the difference of independent value =
4 ÷ 2 = 2
Hence the average rate of change is an increase of 2 points a day
(-3, 3) because it is the intersection point.
Answer:
1,960,135
Step-by-step explanation:
Product = ×
Mutiply your 2 numbers: 8341 × 235
Giving you: 1,960,135
