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noname [10]
3 years ago
14

Which of the following is an arithmetic sequence

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

A sequence that has a contant addition/subtraction to get to the next term

for example:

-3, 0, 3, 6, ...

to get to the next term, we'll need to add 3 each time

Step-by-step explanation:

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Answer:

A

Step-by-step explanation:

g(x) got smaller

A - makes it thinner

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Martin bought a flower vase from a florist. The box in which the vase was packed was shaped like a rectangular prism. What is th
GREYUIT [131]

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In order for the appropriate answer to be given, you need to include the original measurements as well.

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2 years ago
The image below shows two parallel lines cut by a transversal. What is the measure of angle 1?
Yuri [45]

180 - 78 = 102

< 1 = 102*

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Someone please help me on this!
Alexxx [7]

Answer & Step-by-step explanation:

This can be proven with the SAS theorem (side-angle-side)

With a perpendicular bisector, the line it bisects is cut directly in half. This creates two equal sides:

GJ=IJ

and it creates two 90° angles:

∠GJH=∠IJH

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Side-Angle-Side.

:Done

6 0
3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
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