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3 years ago

Help me ASAP please I don't understand it please help It is dued by TONIGHT

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

3 0

So, the first blank is for what kind of angle it is: acute, obtuse, reflex, straight, or right. The second blank is for what the measure of the angle is. You can find that out by looking at the protractor. It should tell you what the measure of the angle is. You can read the protractor by looking at the numbers. The numbers are the degrees of incline the angle measures, which is what you're looking for.

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Which angle has a sine of -1/2 and a cosine of -√3/2

Sergeeva-Olga [200]

$\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)$

$\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}$

$\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}$

$x\in(180^o;\ 270^o)\ therefore\ \boxed{x=30^o+180^o=210^o}$

8 0

3 years ago

Which of the two solids below are similar ?

Pachacha [2.7K]

Answer: I and II.

Step-by-step explanation:

By definition, two solids are similar if their corresponding sides are in the same ratio.

Knowing this, let's find which solids are similar:

Corresponding sides ratio of solids I and II:

$\frac{3}{2}=\frac{2}{\frac{4}{3}}=\frac{5}{\frac{10}{3}}$

$\frac{3}{2}=\frac{3}{2}=\frac{3}{2}$

Corresponding sides ratio of solids I and III:

$\frac{3}{\frac{9}{2}}=\frac{2}{3}=\frac{5}{8}$

$\frac{2}{3}=\frac{2}{3}=\frac{5}{8}$

Corresponding sides ratio of solids II and III:

$\frac{2}{\frac{9}{2}}=\frac{\frac{4}{3}}{3}}=\frac{\frac{10}{3}}{8}}$

$\frac{4}{9}=\frac{4}{9}=\frac{5}{12}$

You can observe that the solids I and II are similar.

3 0

3 years ago

Select the correct answer. Which number has a terminating decimal expansion? A. 2/7 B.√12 C. 5/8 D. 2/11

quester [9]

Answer:

Option C is correct option.

Step-by-step explanation:

We need to determine which number has a terminating decimal expansion.

Terminating decimal

A decimal number that contains a finite number of digits after the decimal point is called terminating decimal .

for example 0.123 is terminating decimal as it has finite number of digits after decimal point.

Now, we will look at each option to find the terminating decimal

A. 2/7

Converting in decimal form: 0.28571....

As it doesn't contain finite numbers after decimal point, so 2/7 is not terminating decimal.

B.√12

Converting in decimal form: 3.46410....

As it doesn't contain finite numbers after decimal point, so √12 is not terminating decimal.

C. 5/8

Converting in decimal form: 0.625

As it contain finite numbers after decimal point, so 5/8 is terminating decimal.

D. 2/11

Converting in decimal form: 0.18181....

As it doesn't contain finite numbers after decimal point, so 2/11 is not terminating decimal.

Therefore, Option C is correct option.

4 0

2 years ago

Solve. Justify your responses. a Given:a║b and c║d, m∠ 4=35° Find: m∠1, m∠2, and m∠3

STALIN [3.7K]

Answer:

m∠1 = 90°

m∠2 = 35°

m∠3 = 55°

Step-by-step explanation:

Find the diagram attached

From the diagram:

$m$

Given that <4 = 35°

$m$

The sum of the angle on a straight line at point A is 180°. Hence:

$90+m$

The sum of angle in the triangle ABC is 180°, hence;

$m$

7 0

2 years ago

The area of a rectangle is expressed as (14x + 28) square feet. If the width of the rectangle is 7 feet, write an expression to

DochEvi [55]

Answer:

The expression for the length of the rectangle is 2x + 4

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of a rectangle is expressed as (14x + 28) square feet. If the width of the rectangle is 7 feet, then the expression for the length of the rectangle would be

Length = Area/ width

= (14x + 28)/7

The numerator has a common factor of 7. Therefore, if we factorize 7 out, it becomes

7(2x + 4)/7

Length = 2x + 4

7 0

3 years ago