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d1i1m1o1n [39]
3 years ago
6

What is the answer to this 177-63

Mathematics
1 answer:
Annette [7]3 years ago
7 0
The answer is 114 to your question
You might be interested in
How to solve the inequality 1/5 ≤ x/15?
MAXImum [283]

Answer:

3 <_ x

Step-by-step explanation:

multiply both sides by 15

1/5 * 15 <_ x

15/5 <_ x

3 <_ x

8 0
3 years ago
For any integer x,x2-x will always produce an even value
Levart [38]

Consider expression x^2-x. First, you can factor it:

x^2-x=x(x-1).

Since x is integer number, then you can see that x-1 is previous integer number (x-1 is 1 unit smaller than x).

Therefore, x-1 and x are two consecutive integers. When you have two consecutive integers, one of them is always even and one is always odd. Multiplying even integer number by odd integer number you always get even integer number.

Thus, x^2-x is always even.

8 0
3 years ago
Find two integers whose sum is -5 andproduct is 4
nirvana33 [79]

Answer:

-1 and -4

Step-by-step explanation:

-1 + -4 = -5

-1 times -4 = 4

give brainiest please!

hope this helps ;)

7 0
1 year ago
when directed to solve a quadratic equation by completing the square, Sam arrived at the equation (x-(5/2))^2= (13/4). which equ
Tasya [4]
We have the following expression:
 (x- (5/2)) ^ 2 = (13/4)
 Let's rewrite the given expression:
 x ^ 2 - 5x + 25/4 = (13/4)
 x ^ 2 - 5x + 25/4 - 13/4 = 0
 x ^ 2 - 5x + 12/4 = 0
 x ^ 2 - 5x + 3 = 0
 Answer:
 
the original equation given to Sam could have been:
 
x ^ 2 - 5x + 3 = 0
7 0
3 years ago
Please answer the question in the picture <br><br> No links please
snow_tiger [21]

Answer:

:)Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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