Answer:
16 people
Step-by-step explanation:
This is a set problem
let first session be a
let second session be b
128 people attended at least one session = a∪b
a. 3/4 attended both session 1&2 = a∩b
b. 7/8 attended session 2 = p(b) i.e population b
c x attended session 1 = p(a) i.e. population a
lets get the figures.
- For both sessions 3/4 × 128 = 96 = a∩b
- For second session 7/8 × 128 = 112 = b
- The formular is a∪b = p(a) + p(b) - a∩b
- a∪b = 128 (they at least one session)
lets substitute into the equation
let p(a) be x
128 = x + 112 - 96
128 = x + 16
x = 112 - no of people that attended the morning session.
But to find those that ONLY attended morning session
x - a∩b
112 - 96 = 16
Answer:
v=1/5 or -6 and apparently this answer is long enough so yh
Given: y²+5y
Converting y²+5y in the form: x²+2ax+a²
Here 2a=5 or a=5/2
Add and subtract (5/2)²
y²+5y+(5/2)²-(5/2)²
Complete the square.
(y+5/2)²-(5/2)²
Simplify
(y+5/2)² - 25/4
Answer: (y+5/2)² - 25/4
Answer:
Let x represent the amount of weeks she is saving up for the bike, and y represents the cost of the bike.
The equation would look like this:
So, let's say the bike costs $2000.
Divide 2000 by 20, and it will give you the x value (or, the amount of weeks it will take)
It will take 100 weeks for her to save $2000 for the bike, if she puts back $20 each week.
