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3 years ago

The missing side length

Mathematics

1 answer:

Anika [276]3 years ago

8 0

No tengo ninguna pista lo siento.

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A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

disa [49]

Answer:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

Step-by-step explanation:

For this case we assume the following probability distribution:

X 5 6 7 8 9 10

P(X) 0.05 0.15 0.33 0.28 0.12 0.07

First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

In order to find the standard deviation we need to find first the second moment, given by :

$E(X^2)=\sum_{i=1}^n X^2_i P(X_i)$

And using the formula we got:

$E(X^2)=(5^2 *0.05)+(6^2 *0.15)+(7^2 *0.33)+(8^2 *0.28)+ (9^2 *0.12 +(10^2 *0.07))=57.46$

Then we can find the variance with the following formula:

$Var(X)=E(X^2)-[E(X)]^2 =57.46-(7.48)^2 =1.5096$

And then the standard deviation would be given by:

$Sd(X)=\sqrt{Var(X)}=\sqrt{1.5096}=1.229$

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During the past six months, 73.2 percent of US households purchased sugar. Assume that these expenditures are approximately norm

lina2011 [118]

Answer:polo g

Step-by-step explanation:

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The amount of snow fall falling in a certain mountain range is normally distributed with a mean of 74 inches, and a standard dev

Nutka1998 [239]

Given that the sample mean is μ=74 and sample standard deviation σₓ= $\frac{σ}{ \sqrt{n}} =\frac{12}{\sqrt{36}} =2$ .

Thge Z- score is $Z=\frac{76.8-74}{2} =1.4$ .

Now we use the Z-score to calculate the required probability.

Refer to standard normal distribution table.

The required probability is

$P(X>76.8) =P(Z>1.4)=1-P(Z$

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