During the past six months, 73.2 percent of US households purchased sugar. Assume that these expenditures are approximately norm
2 answers:
Answer:
0% probability that a household spent more than $16.00 on sugar.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the probability that a household spent more than $16.00 on sugar.
This is 1 subtracted by the pvalue of Z when X = 16. So
has a pvalue of 1.
So there is a 1-1 = 0% probability that a household spent more than $16.00 on sugar.
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<h2>Explanation:</h2><h2></h2>
Hello! remember you have to write complete questions in order to get good and exact answers. Here I'll explain this in a general way assuming the following table:
As you can see, x increases in steps of 1 units. So let's check the difference in y:
So we have a constant difference and we can conclude the table represents a line. Since the line passes through then y is directly proportional to x, so we can write:
Then:
Finally, the equation of the line is: