<span>Finding the square root.</span>
For questions 1-6, let U={0,1,4,9,16,25,36,49,64,81}, A={0,9,16,36,64}, and B={1,9,25,49,81}.
sweet [91]
Answer:Q.2 Does
Step-by-step explanation:
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Answer:
2100
Step-by-step explanation:
Multiply the rate by the time and the weight to find the amount per week.
(2.5%/day)(6 tons)(2000 lb/ton)(7 days/week) = 2100 lb/week
