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Paha777 [63]
3 years ago
9

Keisha solved the following equation:

Mathematics
2 answers:
ad-work [718]3 years ago
4 0

Answer: Step 2 <em> 2x + 8 = 6x + 24   Associative Property of Multiplication </em>

Step-by-step explanation: This is the Question...

<em>Keisha solved the following equation:  </em>

<em>4x − 2x + 8 = 6(x + 4)  </em>

<em> </em>

<em>Step Work Justification </em>

<em>1    2x + 8 = 6(x + 4) Combine like terms </em>

<em>2    2x + 8 = 6x + 24 Associative Property of Multiplication </em>

<em>3 −4x + 8 = 24 Subtraction Property of Equality </em>

<em>4        −4x = 16 Subtraction Property of Equality </em>

<em>5             x = −4 Division Property of Equality </em>

<em> </em>

<em>Which step has an incorrect justification? </em>

<em> A. Step 1 </em>

<em> </em>

<em>B. Step 2 </em>

<em> </em>

<em>C. Step 3 </em>

<em> </em>

<em>D. Step 4</em>

<em></em>

And the answer is, Step 2.

PLEASE GIVE ME BRAINLIEST!!!! PLEASE!!!

slavikrds [6]3 years ago
3 0

Remark

Answer: The second one. The second step removes the brackets on the right. It uses the <em><u>distributive property</u></em> which puts back the common factor that was taken out of the two terms 6x and 24. Quite often the distributive property is useful when presenting a problem to be solved.

The associative property is more of an order thing and that is very useful sometimes as well what it says is that if you have three numbers a + b + c the order which you combine things does not matter.

For example 3 + 4 + 5 could be combined as 3 + 4 = 7;  7 + 5 = 12 or 3 + 5 = 8, 8 + 4 = 12.  

The associative property is useful when adding fractions.

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Cost of 1 notebook is $ 1.85 and cost of 1 pen is $ 0.65

<h3><u>Solution:</u></h3>

Let "a" be the cost of 1 notebook

Let "b" be the cost of 1 pen

Given that John spent $10.65 on 4 notebooks and 5 pens

cost of 1 notebook x 4 + cost of 1 pen x 5 = 10.65

4a + 5b = 10.65 ------ eqn 1

Given that Ariana spent $7.50 on 3 notebooks and 3 pens

3a + 3b = 7.50 ----- eqn 2

Let us solve eqn 1 and eqn 2 to get the values of "a" and "b"

Multiply eqn 1 with 3

12a + 15b = 31.95  ---- eqn 3

Multiply eqn 2 with 4

12a + 12b = 30 ------ eqn 4

Subtract eqn 4 from eqn 3

12a + 15b = 31.95

12a + 12b = 30

(-) ---------------------

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