The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
Answer:
x=7
Step-by-step explanation:
7=2x-7
-2x-7-7
-2x=-14
x=-14÷2
x=-7
Answer:
Length of side of rhombus is
Step-by-step explanation:
Given Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC. We have to find the length of side of rhombus.
It is also given that AB=a and AC=b
Let side of rhombus is x.
In ΔCEF and ΔCBA
∠CEF=∠CBA (∵Corresponding angles)
∠CFE=∠CAB (∵Corresponding angles)
By AA similarity rule, ΔCEF~ΔCBA
∴ their sides are in proportion
![\frac{EF}{AB}=\frac{CF}{AC}](https://tex.z-dn.net/?f=%5Cfrac%7BEF%7D%7BAB%7D%3D%5Cfrac%7BCF%7D%7BAC%7D)
⇒ ![\frac{x}{a}=\frac{b-x}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Ba%7D%3D%5Cfrac%7Bb-x%7D%7Bb%7D)
⇒ ![xb=ab-ax](https://tex.z-dn.net/?f=xb%3Dab-ax)
⇒ ![x(a+b)=ab](https://tex.z-dn.net/?f=x%28a%2Bb%29%3Dab)
⇒ ![x=\frac{ab}{a+b}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bab%7D%7Ba%2Bb%7D)
Hence, length of side of rhombus is
5/12=10/24 and 7/8= 21/24, add those and you will get 31/24 subtract 31 from24 and get 7 your new fraction is 1 7/24 that is 5/12 + 7/8 in simplest form