Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:




The area of A is:

This gives:

Open bracket

The area of B is:


Substitute: 

Open brackets


Expand


We have that:

This gives:

Collect like terms


Using quadratic calculator, we have:
or
--- approximated
But the width can not be negative; So:

Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b
so ur equation is : y = 7x - 5 <==
7 because a(one side)= 1/sqrt2 * hypotenuse (7*sqrt2) THis equals 7
Answer:
90
Step-by-step explanation: