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4 years ago

5

What number would go into the box?

1 answer:

loris [4]4 years ago

6 0

8. When dealing with exponents like x^2, multiplication is like addition and division is like subtraction (x^2*x^3=x^5, x^3/x^2=x). So, for this one, we can get rid of the X’s and rewrite as this: p+6-2=12. If we solve this, we see that the answer is 8.

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*Offering 50 points and brainliest to anyone can explain steps* (Pic attached)

olchik [2.2K]

D because the shaded region has one side and subtract by pie and substitute to get this answer.

7 0

3 years ago

If a 30% discount is put on an item, and the sale price is $206.50, then what was the original price?

s2008m [1.1K]

Answer:

295

Step-by-step explanation:

.3 x 295 = 88.5

295 - 88.5 = 206.5

8 0

4 years ago

Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

4 years ago

Which is an equation in point slope form of the line that passes through the points (7 -8) and has a slope of -3

Nataly [62]

Y+8 = -3(x-7)
Distribute the -3
y +8 = -3x +21
Subtract 8 from both sides
Y = -3x +21 -8
Y= -3x+13

3 0

3 years ago

Choose the correct domain and range for the following graph: <br><br> GUYS PLZ HELP !!!

algol [13]

The last choice, do an is the x value so you would look at the x values which is -4, 6. And range is the y values so the highest y value and the lowest. Which is -5,4. So you answer is the last option

4 0

3 years ago