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Leona [35]
2 years ago
6

A box contains 8 green balls, 16 red balls, 10 white balls, and 6 pink balls.

Mathematics
2 answers:
Pepsi [2]2 years ago
8 0
The probability of drawing a white ball is 1/4

Explanation:
When we solve for probability, we want to find out how many of something there is out of its total. So in this case, we want to see how many white balls there are out of the totals balls in the box. We already know that there are 10 white balls, so we need to figure out the total balls in the box, by adding up. 8 green balls + 16 red balls + 10 white balls + 6 pink balls = 40 balls in total. Now we know that the fraction would be 10/40, as there are 10 white balls out of 40 total balls. Finally, we simplify the fraction to 1/4, therefore the answer is B.
nydimaria [60]2 years ago
3 0
You find probability of drawing the marble by doing specific marble/total marbles. To find total marbles, add all the marbles:
8 + 16 + 10 + 6 = 40
Since we are searching for the probability of drawing the white marble and there are 10 white marbles,:
10/40 simplifies to 1/4 so b!
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The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.  

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = β

  • If β < 1, then the series converges
  • If β > 1, then the series diverges
  • If β = 1, then the series inconclusive

Here a_{k} = \frac{(x+2)^{k}}{\sqrt{k} }  and  a_{k+1} = \frac{(x+2)^{k+1}}{\sqrt{k+1} }

   

Now limit is taken,

\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }| = \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|

= \lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|

= \lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|

= |{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}

= |{x+2 }| < 1

- 1 < {x+2 } < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

 

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

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