Please write out the entire question so we can do our best to assist you with the most logical response.
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Answer:
see explanation
Step-by-step explanation:
the sum to n terms of an arithmetic sequence is
=
[2a + (n - 1)d ]
where d is the common difference and a is the first term
here d = 9 - 7 = 7 - 5 = 2 and a = 5, hence
=
[(2 × 5) + 2(n - 1) ]
=
(10 + 2n - 2)
=
(2n + 8)
= n² + 4n
When sum = 165, then
n² + 4n = 165 ← rearrange into standard form
n² + 4n - 165 = 0 ← in standard form
(n + 15)(n - 11) = 0 ← in factored form
equate each factor to zero and solve for n
n + 15 = 0 ⇒ n = - 15
n - 11 = 0 ⇒ n = 11
but n > 0 ⇒ n = 11
Answer:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
The number -5 is anything but natural number.
It is an integer (Z) ,a rational number (Q) and a real number (R) .