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gulaghasi [49]
3 years ago
9

If f(x) = x^4-x^3+x^2 and g(x)= -x^2, where x does not = 0, what is (f/g)(x)?

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

For this case we have the following functions:

f (x) = x ^ 4-x ^ 3 x ^ 2\\g (x) = - x ^ 2

By definition of composition of functions we have to:(f \ g) (x) = \frac {f (x)} {g (x)}

So:

\frac {f (x)} {g (x)} = \frac {x ^ 4-x ^ 3 x ^ 2} {- x ^ 2} = \frac {x ^ 4} {- x ^ 2} +\frac {-x ^ 3} {- x ^ 2}+ \frac {x ^ 2} {- x ^ 2} =

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

\frac {f (x)} {g (x)} = - x ^ 2+x-1

ANswer:

(\frac {f} {g}) (x) = - x ^ 2 +x-1

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