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posledela
3 years ago
13

PLEASE HELP WITH MATH! Quick problem. :)

Mathematics
2 answers:
Maru [420]3 years ago
8 0
6^2 = 36
5 x 6 = 30
36 - 30 = 6
6 - 3 = 3
The answer is 3

docker41 [41]3 years ago
7 0
The answer is three.

6^2 - 5(6) -3

36 - 30 - 3

6 - 3
3
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Aleonysh [2.5K]
f(x) = (x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} )

\text {When } f(x) = 0 :

(x -  \dfrac{2}{9} )(x +  \dfrac{1}{2} ) = 0

(x -  \dfrac{2}{9} ) = 0  \text { or }  (x +  \dfrac{1}{2} ) = 0

x =  \dfrac{2}{9}  \text { or } x =  -\dfrac{1}{2}

3 0
3 years ago
Help please!<br><br> A.<br><br><br> B.<br><br><br> C.<br><br><br> D.
elixir [45]

Answer:

D.

b = 175; which is the initial # of pages to start

Step-by-step explanation:

you can find the slope to find b or y-intercept (x=0) for equation

y=mx+b

to find m = (y2-y1)/(x2-x1)

(x1,y1) = (9, 100)

(x2, y2) = (15, 50)

m = (50-100) / (15-9) = -50/6 = -25/3

let use point (15, 50)

y=mx+b

50 = -25/3*x + b

50 = (-25/3)*(15) + b

50 = -125 + b

b = 175; which is the initial # of pages to start

3 0
3 years ago
The ratio of children to adults at family movie night is 5 to 4. A total of 72 people showed up at this weeks movie night. How m
N76 [4]
The answer is 40 I think
7 0
3 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
Russell bought a $1,240 sound system on an installment plan. The installment plan included a 20% down payment and 18 monthly pay
KonstantinChe [14]
The down payment is $248
The total amount of monthly payments is 62

7 0
2 years ago
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