Bakabaga anabahakan agajaba Avanavajakab
The two angles form a straight line and need to equal 180 when added together:
7x + 28 + 33 = 180
Simplify:
7x + 61 = 180
Subtract 61 from both sides
7x = 119
Divide both sides by 7
X = 17
Answer: B.17
The system of the linear systems of equation using substitution is;
- x = 2, y = 2
- x = -20, y = -1
<h3>Linear equation</h3>
3x-y=4
x+2y=6
from (2)
x = 6 - 2y
substitute into (1)
3x-y=4
3(6 - 2y) - y = 4
18 - 6y - y = 4
- 6y - y = 4 - 18
-7y = -14
y = 2
Substitute into
x+2y=6
x + 2(2) = 6
x + 4 = 6
x = 6 - 4
x = 2
2. 2x-y= -39
x+y= -21
From (2)
x = -21 - y
substitute into
2x-y= -39
2(-21 - y) - y = -39
-42 - 2y - y = -39
- 2y - y = -39 + 42
- 3y = 3
y = 3/-3
y = -1
substitute into
x+y= -21
x + (-1) = -21
x - 1 = -21
x = -21 + 1
x = -20
3. 2x+y =11
6x-5y =9
Learn more about linear equation:
brainly.com/question/4074386
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Answer:
(A)![[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]](https://tex.z-dn.net/?f=%5Bx-%282%2Bi%29%5D%5Bx-%282-i%29%5D%5Bx-%5Csqrt%7B2%7D%5D%5Bx%2B%5Csqrt%7B2%7D%5D)
Step-by-step explanation:
A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:
We apply the following to find the factored form of the polynomial.
- If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.
- If the polynomial has an irrational root
, where a and b are rational and b is not a perfect square, then it has also a conjugate root 
.
Therefore, the factored form of the polynomial is:
Answer:
False
Step-by-step explanation:
for a rational number expressed as (A / B) where A & B are integers
if the numerator (A) is zero, then (A/B) is simplify zero
i.e (A / B) = (0 / B) = 0
however if the denominator (B) is zero, then by definition any value divided by zero is undefined.
(A / B) = (A / 0) = {undefined}
