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4 years ago

Someone help me with this please?

Mathematics

2 answers:

MariettaO [177]4 years ago

7 0

The question's cut off. repost & ill see if i can help (:

WINSTONCH [101]4 years ago

6 0

I am sorry, but I think that the question is cut off. Perhaps you can re-post it for us to see it completely? I would be happy to help! :)

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Ow many cans of paint are needed to cover an area of 2,200 square units if one can of paint covers an area of 400 square units?

salantis [7]

The number of cans needed to paint an area covering 2,200 sq. units will be given by:
number of cans=[area required to be painted]/[area that 1 can of paint can cover]
=2200/400
=5.5
Therefore we conclude that we will need 5.5 cans of paint

6 0

3 years ago

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Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

4 years ago

Quadrilateral PQRS is inscribed in a

AveGali [126]

Answer: H

Step-by-step explanation:

8 0

3 years ago

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Kazeer [188]

Answer:

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Step-by-step explanation:

= (3 - 1)(x + 2)(x)

= (2)(x + 2)(x)

= (2x + 4)(x)

= 2x² +4x

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4 years ago

What is the vertex form of the quadratic function that has a vertex at (5, 4)

MArishka [77]

Tbh I’m not sure
I think it’s D-y=5(x - 5)2 - 3
I’m sorry if this is wrong

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3 years ago