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3 years ago

I need help plz and explain

Mathematics

1 answer:

rewona [7]3 years ago

3 0

I think that its B but im not entirely sure about it

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Which of these functions has a domain of all real numbers except x=4.1?

nika2105 [10]

Answer:

$(A)y=\frac{2.5}{x-4.1} + 2.8$

Step-by-step explanation:

In the expressions, the value at which the domain of the function will be the set of all real numbers except x=4.1 is the value at which 4.1 makes the denominator equal to zero, i.e makes the fraction undefined.

Given the options

$(A)y=\frac{2.5}{x-4.1} + 2.8$

Setting the denominator to zero, x-4.1=0, x=4.1. The fraction is undefined at x=4.1

$(B)y=\frac{2.8}{x+4.1} -2.5$

Setting the denominator to zero, x+4.1=0, x=-4.1. The fraction is undefined at x=-4.1

$(C)y=\frac{4.1}{x-2.8} +2.5$

Setting the denominator to zero, x-2.8=0, x=2.8. The fraction is undefined at x=2.8

$(D)y=\frac{4.1}{x-2.5} +2.8$

Setting the denominator to zero, x-2.5=0, x=2.5. The fraction is undefined at x=2.5

Therefore, function that has a domain of all real numbers except x=4.1 is:

$(A)y=\frac{2.5}{x-4.1} + 2.8$

4 0

3 years ago

Why is x = 4 a solution to the proportion StartFraction 14 over x EndFraction = StartFraction 56 over 16 EndFraction?

mars1129 [50]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{14}{x}$ = $\frac{56}{16}$ ( cross- multiply )

56x = 14 × 16 = 224 ( divide both sides by 56 )

x = 4

6 0

3 years ago

Read 2 more answers

What is the area of this ^2

Ad libitum [116K]

<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

$Area = \frac{1}{2} \times base \times height \:$

Now put the value as -> base= 5 and height= 12

$Area = \frac{1}{2} \times base \times height \: \\ Area = \frac{1}{2} \times 5 \times 12 \\ Area = \frac{1}{ \cancel2} \times 5 \times \cancel{12}^{ \: \: 6} \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}$

Now add both areas for your answer

$Area{ \tiny{1}} = 12 {units}^{2} \\ Area{ \tiny2} = 30 {units}^{2} \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}$