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zubka84 [21]
4 years ago
14

ASAP

Mathematics
1 answer:
Phoenix [80]4 years ago
8 0
81 is a counter example of the conditional statement given.

81 has factors other than itself, 1 and the square root of 81 which is 9.

81 has factors of 3 and 27 which are not listed.
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Using the following triangle, what is the cosine of angle B?
stealth61 [152]

Hello!

To find cosine, use the formula cos = adjacent / hypotenuse.

According to angle B, adjacent of angle B is side A, and the hypotenuse is side c because the hypotenuse is always opposite the right angle.

Therefore, the cosine of angle B is a/c.

3 0
4 years ago
The solid shape is made from a cylinder and a hemisphere.
Yuki888 [10]

The solid shape is made from a cylinder and a hemisphere. The radius of the cylinder is equal to the radius of the hemisphere. The cylinder has a height of 10 cm. The curved surface area of the hemisphere is 32π cm2.

Minutes

Median 170

Lower quartile 100

Upper quartile 220

3 0
3 years ago
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Peaches come in large and small cylindrical cans. The larger can has a radius and height that are both four times longer than th
Bogdan [553]
The answer would be D, not sure if you still need it.
8 0
3 years ago
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( 27 thousands 3 hundreds 5 ones) x 10=
kirill [66]

Answer:

273,050

Step-by-step explanation:

(27000+300+5)×10

=27305×10

=273050

8 0
3 years ago
Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)
Allisa [31]
Part A:

Given the function f(x)=x+2\cos(x), the absolute maximum or minimum occurs when f'(x)=0.

f'(x)=0 \\  \\ \Rightarrow1-2\sin{x}=0 \\  \\ \Rightarrow2\sin{x}=1 \\  \\ \Rightarrow\sin{x}= \frac{1}{2}  \\  \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}

Using the second derivative test,

f''(x)=-2cosx \\  \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732

Since the second derivative gives a negative number, the given function has a maximum point at x=\frac{\pi}{6}.

And the maximum point is given by:

f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\  \\ =0.5236+2(0.8660)=0.5236+1.732 \\  \\ =\bold{2.256}

i.e. \left(\frac{\pi}{6},\ 2.256\right)



Part B:

Given the function f(x)=e^{-x}-e^{-2x}, the absolute maximum or minimum occurs when f'(x)=0.

f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\  \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\  \\ \Rightarrow x=0.6931

Using the second derivative test,

f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\  \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\  \\ =-0.5

Since the second derivative gives a negative number, the given function has a maximum point at x=0.6931.

And the maximum point is given by:

f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\  \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}

i.e. (0.693, 0.25)
3 0
3 years ago
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