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sergey [27]
3 years ago
5

In triangle RST, BK is the mid segment between sides RS and RT. If ST is 18 units, how long is BK?

Mathematics
1 answer:
Allushta [10]3 years ago
3 0

Answer:

BK=9

Step-by-step explanation:

A midsegment is one half of the length of the base. So, If the base, which is ST is 18, the midsegment will be 18/2=9

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Un escalador sube 225m de altura. El asenso lo hizo en 3 etapas. En la primera subio un quinto en la, en la tercera un cuarto. ¿
kiruha [24]

Answer:

Segunda etapa= 123.75 metros

Step-by-step explanation:

Altura total= 225 metros

<u>En la primera estapa subió el 20% (un quinto):</u>

Primera etapa= 225*0.2= 45 metros

<u>En la tercera etapa subió 25% (un cuarto):</u>

Tercera etapa= 225*0.250 56.25 metros

Ahora debemos determinar cuánto subió en la segunda etapa:

Segunda etapa= altura total - total subido

Segunda etapa= 225 - (45 + 56.25)

Segunda etapa= 123.75 metros

6 0
3 years ago
Need help with math PART 3
mixas84 [53]

Answer:

1. x=40

2. x=17

3. x=5

4. x=83

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
The endpoints of a side of rectangle ABCD in the coordinate plane are at A(1,4) and
andrew-mc [135]

Answer:

<em>y = - x + 5 </em>

Step-by-step explanation:

A(1, 4)

B(4, 1)

m_{AB} = \frac{1-4}{4-1} = - 1

y - 1 = - 1 ( x - 4 )

<em>y = - x + 5</em>

6 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
93 round to the nearest hundred
klasskru [66]
5 or more add one more
4 or less could care less(aka don't change the number)
93 right and round it to the nearest hundreds
So ig 93 than you look at the tens is it more than 5 or less than 4?
It's more than 5 so you add another number on the hundreds since there is nothing on the hundred place it is 100(Answer)if it was less than 4 it would just be 0. Hope I helped
6 0
3 years ago
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