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maw [93]
3 years ago
7

Divide: ((p^2-q^2)/(p+q)) ÷ ((p-q)/(p+q))

Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0

Answer:

The answer is p+q

Step-by-step explanation:

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MATH PROBLEM NEED HELP NOW! (look at photo)
Alexandra [31]

Answer:

I don’t see photo

Step-by-step explanation:

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4 years ago
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Put 1.09, 1.0, 1.9, 1.19, 1.1 on a number line in order?
Luden [163]

Answer:

1.0, 1.09, 1.1, 1.19, 1.9

Step-by-step explanation:

Basic ordering of decimals

7 0
3 years ago
Graph:<br> 4p+1&gt;-7 or 6p+3&lt;33
Hoochie [10]
This problem involves only one variable, so we stick to one horizontal line, which represents p values.  There is no vertical axis.

If 4p+1>-7, we solve for p by subtracting 1 from both sides:  4p>-8; then we divide both sides by 4, obtaining p>-2  Draw an open circle at p=-2 and from this open circle draw an arrow to the right.

If 6p+3<33, 6p<30.  Dividing both sides by 6, p<5.  Draw an open circle at p=5 and from this open circle draw an arrow to the right.

Now determine the p values for which your two arrows coincide.  The first arrow begins at p=-2 and extends to the right from there; the second arrow begins at p=5 and extends to the left.  So, the only coincidence of the two arrows is between -2 and +5 (noting that the arrows do NOT touch p=-2 or p=5).

The solution set can be writtten as -2<p<5, or as (-2,5).
3 0
4 years ago
Anyone know how to do this people are answering the question but aren’t choosing two anwsers
katovenus [111]

Answer:

Option B and Option D are the two answers

7 0
3 years ago
The table shows a proportional relationship between the number of pounds of bananas purchased and the total cost of bananas.
Liula [17]

Answer:

Choice A, C and E

Step-by-step explanation:

<em>Your table is poorly presented</em>

Given

x      y

\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}

First, we calculate the constant of proportionality (k)

k = \frac{y}{x}

For (3,1.47)

k = \frac{1.47}{3}

k = 0.49

For (5,2.45)

k = \frac{2.45}{5}

k = 0.49

For (9,4.41)

k = \frac{4.41}{9}

k = 0.49

From the above calculations, the constant of proportionality is 0.49.

So, the usable rows must also have 0.49 as their constant of proportionality

<u>Choice A</u>

(x,y) = (2,0.98)

k = \frac{0.98}{2}

k = 0.49 --- <em>This is usable</em>

<em />

<u>Choice B</u>

(x,y) = (7,4.45)

k = \frac{4.45}{7}

k = 0.64 --- <em>This is not usable</em>

<em />

<u>Choice C</u>

(x,y) = (6,2.94)

k = \frac{2.94}{6}

k = 0.49 --- <em>This is usable</em>

<em />

<u>Choice D</u>

(x,y) = (1,0.54)

k = \frac{0.54}{1}

k = 0.54 ---- <em>This is not usable</em>

<em />

<u>Choice E</u>

(x,y) = (8,3.92)

k = \frac{3.92}{8}

k = 0.49 --- <em>This is usable</em>

5 0
3 years ago
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