Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer:
.27
Step-by-step explanation:
Answer:
2.82 seconds (3 sf)
Step-by-step explanation:
s = ut + 0.5at²
6 = -95(sin25)t + 0.5(32)t²
16t² - 40.14873487t - 6 = 0
t = 2.818501699, -0.1419193751
t is time so can't be negative.
Therefore, t = 2.82s (3 sf)
