Question

the construction of a 1000 suit luxury hotel requires the installation of 12 outlets and 6 light fictures per suit . The companys standard productivity for a two electrician crew is 20 minutes per light fixture and 30 minutes per outlet. Using eighteen crews working at a 0.8 efficiency factor and a 10hr work day with a half an hour lunch break , the duration of this construction activity (days,hours) is most nearly how much

Answer 1

Answer:

Hours = 8000

Days = 46.78

Explanation:

The duration of this construction activity can be calculated as follows

DATA

No. of suits = 1000

Outlets to be installed = 12/suit

Standard productivity for outlet = 30mins

Fixtures to be installed = 6/suit

Standard productivity light fixture = 20mins

Working hours per day = 10 hours - 0.5 lunch break

Working hours per day = 9.5 hours

No. of crews = 18

Solution

Total time to fix = No.of suits x no. of installations x Standard time

Total time to fix = (1000 x 12 x 30mins ) + ( 1000 x 6 x 20mins)

Total time to fix = 480000 mins

Total time to fix = 480000/60mins = 8000 hours

Duration in days = Total time / (hrs per day x mo. of crews)

Duration in days = 8000 hours / (9.5 x 18)

Duration in days = 8000/171

Duration in days = 46.78 days