X actually equals the cube root of 6
![{x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%20-%206%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B3%7D%20%20%3D%206%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B6%7D%20)
Answer:
x=-1
Step-by-step explanation:
2x+3/4(4x+16)=7
2x+(3x12)=7--->distributive property
2x+3x+12=7
5x+12=7--->addition property
5x=-5--->subtraction peroperty
x= -1---?division property
Answer:
787
Step-by-step explanation:
i took the test
Answer:
Yellow and purple
Step-by-step explanation:
Part A: Explain why the x-coordinates of the points where the graphs of
the equations y = 4-x and y = 2x + 3 intersect are the solutions of the
equation
4-x = 2x + 3.
Because the point where the graphs intersect is a point that meets both rules (functions) y = 4 - x and y = 2x + 3 meaning that y from y = 4 - x equals y from 2x + 3 and also both x have the same value.
Part B: Make tables to find the solution to 4-x = 2x + 3. Take the integer values of x between -3 and 3.
x values 4 -x 2x + 3
-3 4-(-3)=7 2(-3)+3 =-3
-2 4-(-2)=6 2(-2)+3 =-1
-1 4-(-1)=5 2(-1)+3 = 1
0 4-0=4 2(0)+3 = 3
1 4-1=3 2(1)+3=5
2 4-2=2 2(2)+3 = 7
3 4-3=1 2(3)+3 = 9
The the solution is between x = 0 and x =1
Part C: How can you solve the equation 4-x = 2x + 3 graphically?
Draw in a same graph both functions y= 4 - x and y = 2x +3.
Then read the x-coordinates of the intersection point. That is the solution.
