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timama [110]
3 years ago
11

How do you do this, thanks for helping

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

A: (-7, -4)

B: (-3, 8)

Step-by-step explanation:

Ordered pairs are (x,y).

Count the lines and see:

A is 7 to the left and 4 down so (-7, -4)

B is 3 to the left and 8 up so (-3, 8)

REMEMBER X IS ALWAYS FIRST!!

Does this answer make sense? YES! Because quadrant II all the pairs will be (-#, #) and in quadrant III the pairs will be (-#, -#)

Hope that helps!

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</span><span>[B]:  The 8 in the tenths place is 10 times the value of the 8 in the hundredths place.
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\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

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\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

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