two airplanes leave an airport at the same time and travel opposite directions. one plane travels 81 km/h slower than the other.
If the two planes are 6140 km apart after 4 hours, what is the rate of each plane?
1 answer:
Answer:
The speed of the faster plane is 899 km/hr
The speed of the slower plane is 824 km/hr
Step-by-step explanation:
Equation for faster plane:
(1) +d+=+s%2A4+
Equation for slower plane:
(2) +6892+-+d+=+%28+s+-+75+%29%2A4+
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