The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
the answer is 5 dimes and 1 nickel.
hope this helps <3
Let's you and me discuss a few things that you already know:
-- What's a y-intercept ?
The y-intercept on a graph is the place where it crosses the y-axis.
-- That's the value of 'x' at the y-intercept ?
The y-intercept is on the y-axis, so 'x' is zero there.
-- Good ! So how would you find the y-intercept of a function ?
You say that x=0 and look at what 'y' is.
-- Very nice. What's the function in this question ?
The function is
f(x) [or 'y'] = x⁴ + 4x³ - 12x² -32x + 64 .
-- Excellent. What's the value oif that function (or 'y') when x=0 ?
It's just 64 .
-- Beautiful.
Are there any answer choices that cross the y-axis at 64 ?
How many are there ?
There's only one.
It's the upper one on the right hand side.
Add them all up and divide 6 (the number of terms given). The answer is 9.66 or 9.7 rounded to the nearest tenth.
Answer:c
Step-by-step explanation:I just did this one and got it correct
