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Kryger [21]
2 years ago
10

Complete the statement. Trapezoids are parallelograms

Mathematics
2 answers:
Viktor [21]2 years ago
6 0

Trapezoids are parallelograms.<em> NOT !</em>

Lady bird [3.3K]2 years ago
4 0

Answer:

Step-by-step explanation:

(A) The given statement is:A square is a parallelogram-------A square is always a parallelogram (By properties of parallelogram)(B) The given statement is:A rectangle is a trapezoid----------A rectangle is never a trapezoid.(C) The given statement is:A rhombus is a square--------A rhombus is sometimes a square.(D) The given statement is:A quadrilateral is a kite--------A quadrilateral is sometimes a kite.

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What would be the appropriate units and intervals to use along the x- and y-axes
Vika [28.1K]

X axes are supposed to be positive and the y is negative.

3 0
3 years ago
Given right triangle A w/a hypotenuse length of x+4 and a leg of x, and right triangle B, w/ a hypotense length of 3y and a leg
alex41 [277]

Answer:

Value is x=8 and y=4

Step-by-step explanation:

Given : A right triangle 'A'  hypotenuse length of x+4 and a leg of x,

and right triangle 'B' hypotenuse length of 3y and a leg length of y+4

To find : For what values of x and y are the triangles congruent by HL?  

Solution :

Triangle A,

Hypotenuse: x+4

Leg: x

Triangle B,  

Hypotenuse: 3y

Leg: y+4  

Since the triangle A and B are congruent so, the sides of triangles are equal.

x+4=3y    (Hypotenuse are equal)  ..........[1]

and x=y+4   (Legs are equal)   ..........[2]

Solving the equation of system,

Put the value of x from [2] in [1],

x+4=3y

y+4+4=3y

8=2y

y=4

Substitute y in [2],

x=y+4

x=4+4

x=8

Therefore, The value of x=8 and y=4

Verifying for the values of x and y:

Triangle A,

Hypotenuse: x+4=8+4=12

Leg: x=8

Triangle B,  

Hypotenuse: 3y=3(4)=12

Leg: y+4=4+4=8

Both hypotenuses and both legs are equal hence they are congruent.

6 0
2 years ago
There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller n
Mrrafil [7]

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

<u>1) Translate the information into equations</u>

"One is 7 more than twice the other"

⇒ y=2x+7

"The sum of the numbers is 43"

⇒ x+y=43

<u>2) Use substitution to solve for the smaller number</u>

x+y=43

Plug the equation y=2x+7 into the above equation

x+(2x+7)=43\\x+2x+7=43\\3x+7=43

Subtract both sides by 7

3x+7-7=43-7\\3x=36

Divide both sides by 3 to isolate x

\frac{3x}{3} = \frac{36}{3} \\x=12

Therefore, the smaller number equates to 12.

<u>3) Use substitution to solve for the greater number</u>

x+y=43

Plug in x as 12

12+y=43

Subtract both sides by 12 to isolate y

12+y-12=43-12\\y=31

Therefore, the greater number equates to 31.

I hope this helps!

3 0
3 years ago
In November, the price of a GizmoPhone was double the price in March. In December, the price was $57, which was $29 less than th
Jet001 [13]
<span>December = $57

</span><span>In December, the price was $57, which was $29 less than the price in November then November price was: $57 + $29 = $86
</span><span>In November, the price of a GizmoPhone was double the price in March. so March: $86 x 2 = $172

answer: the price </span>of a GizmoPhone in March was $172
7 0
3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
3 years ago
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