Find the value of x for which line a is parallel to line b

I need help with this

Olenka [21]

Answer:

Tom

Step-by-step explanation:

After you convert them to decimals 131/593 is 0.22091062394 while 2/9 is 0.22222222222

4 0

3 years ago

6 less than the product of 4 and a number n is -12. What is the number?

torisob [31]

Answer:-3/2

Step-by-step explanation:

4n-6=-12

4n=-6

n=-6/4

n= -3/2

6 0

3 years ago

How many liters of water containing 7 grams of salt per liter must be combined with x liters of water which contains y grams [y

iVinArrow [24]

Answer:

$\frac{(2-y)x}{5}\text{ litres}$

Step-by-step explanation:

Let l litre of 7 grams of salt per litre is combined with x litres of water which contains y grams of salt per litre to yield a solution with 2 grams of salt per litre.

Thus,

Salt in l litre + salt in x litre = salt in resultant mixture

7l + xy = 2(l +x)

7l + xy = 2l + 2x

7l - 2l = 2x - xy

5l = x(2-y)

$\implies l =\frac{x(2-y)}{5}$

Hence, $\frac{x(2-y)}{5}$ litres of 7 gram of salt per litre is mixed.

5 0

3 years ago

In a small church in rural pennsylvania, the first pew can fit only 6 people. the second pew can fit 8, and the third can fit 10

IgorC [24]

An=a1+(n-1)d
A15=6+(15-1)2
A15=6+(14)2
A15=6+28
A15=34
Answer=34

7 0

3 years ago

Read 2 more answers

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$