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ivann1987 [24]
3 years ago
11

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

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Step-by-step explanation:

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What is the midpoint of the x-intercepts of f(x)=(x-2)(x-4
NARA [144]
Well, we know that the x-intercepts are (0,2) and (0,4).  That means that the midpoint is just (0,3)

You can also use the midpoint formula:

M=( \frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

If you thought my answer helped and was correct, please label my answer the brainliest for others to see.
7 0
3 years ago
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What are some solutions of the question 3x^2-5x+2=0?
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

3x²-5x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

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either x-1=0 which gives x=1

or 3x-2=0

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7 0
3 years ago
(1/4)^3z-1 =16^z+2*64^z-2<br><br> Z=___<br><br> Please help
wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274

Hence, the value of Z = 0.198877274

8 0
3 years ago
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Solve for x.
Tamiku [17]
The answer to the question is a

5 0
3 years ago
I WILL GIVE BRAINLIEST!!!
Katyanochek1 [597]

Answer:

g(x) = (f-x)

Step-by-step explanation:

It's relection across the y axis

==> g(x) = (f-x)

6 0
3 years ago
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