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likoan [24]
3 years ago
10

Which of the following statements about the work shown below is true?

Mathematics
1 answer:
torisob [31]3 years ago
3 0

Answer:

A is your Answer

Step-by-step explanation: UR WELCOME


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HELP ME ITS TIMED AND I WILL GIVE BRAINLIEST!!!!!
Olegator [25]

To find the gradient of a line we first hv to find the formula

so Gradient=√X1-x2and √y1-y2

((-2,1) and (0,-5)) line 1

line 2(0,-1) and (1,0)

first we will work for line 1

X1 is -2

X2 is -0

Y1 is 1

Y2 is -1

so y=x-1

so we substitute the values

1--1=-2--0

so,

1+1=-2+0

2=-2

-0

So the equation 1 line 1 is not true

we will now go to equation 2 line 2

the equation is 3x+y=-5

we substitute the values

3(-2--0)+1--1=-5

3(-2)+-2=-5

-6+-2=-5

-8= -5

group like terms

Ur answer should look like this -3

So the answer is 3x+y=-5

7 0
3 years ago
If u= <4,5> and v= <0,-1>, find 2v+5u
GaryK [48]

Answer:

<20,23>

Step-by-step explanation:

u= <4,5> and v= <0,-1>

2v = 2*<0,-1> = <0,-2>

5u = 5* <4,5> = <20,25>

2v+5u = <0,-2> + <20,25>

            = <20,23>

4 0
3 years ago
Read 2 more answers
The graph has y-intercept (0, 6) and contains the point (2, 1).
prisoha [69]

Answer:

5x + 2y = 12

Step-by-step explanation:

Direction factor = (2, 1) - (0, 6) = (2, -5)

So, normal factor = (5, 2)

Line: 5x + 2y = k

(0, 6) -> L: 0 + 12 = 12 = k

L: 5x + 2y = 12

5 0
3 years ago
HWEEEEEEEEEEEEELPPPPEPEPLpelpelepelpelepelpeleplepeleplepleplpeplepeeplepelpeplelepelplplPLEPLEp"LPELp"Lp'l
labwork [276]
The answer would be 28 but couldnt you have done this yourself?

7 0
3 years ago
Read 2 more answers
18.) A cylinder and a cone have the same radius and<br> the same volume. How do the heights compare?
mart [117]

Answer:

If a cone and a cylinder have the same base and the same height, then the volume of the cone is of the volume of the cylinder. For example, the cylinder and cone shown here both have a base with radius 3 feet and a height of 7 feet. The cylinder has a volume of cubic feet since .

Step-by-step explanation:

6 0
3 years ago
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