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Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

5 0

Answer: #3 is y=-3/2x+1 (or 1 1/2x)

#2: -3/2

#1: 1

Step-by-step explanation:

To find the slope, make a right triangle with the line The 3 is the how many up, the 2 is the how many across. It is negative because it allows down to the right.

To find the intercept, look at where the line cross the vertical line. Which in this case, is 1

Let me know if you have any questions and Mark me as brainliest if this helps!

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3 years ago

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3 years ago

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We are tasked to solve for the ratio of the two boxes. Boxes are cubes. We can use the formula in solving the surface area of the box as shown below:
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3 years ago

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3 years ago

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago