Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
Answer:
And we can find this probability using the normal standard distribution table and we got:
And the percentage faster than 13.28 seconds would be 91.9%
Step-by-step explanation:
Let X the random variable that represent the runtimes of a population, and for this case we know the distribution for X is given by:
Where
and
We want to find this probability:
And we can use the z score formula given by:
Using this formula we have:
And we can find this probability using the normal standard distribution table and we got:
And the percentage faster than 13.28 seconds would be 91.9%
Answer:
its C
Step-by-step explanation:
I just saw that
Answer: B
Step-by-step explanation:
Answer:
8+6-10+2+15-3-7-5+2-15-8+10 = 5
Step-by-step explanation: